https://github.com/jiadaizhao/LeetCode/tree/master/0702-Search%20in%20a%20Sorted%20Array%20of%20Unknown%20Size
int search(const ArrayReader& reader, int target) {
int hi = 1;
while (reader.get(hi) < target) {
hi <<= 1;
}
int lo = hi >> 1;
while (lo <= hi) {
int mid = lo + (hi - lo) / 2;
int val = reader.get(mid);
if (val == target) {
return mid;
}
else if (val < target) {
lo = mid + 1;
}
else {
hi = mid - 1;
}
}
return -1;
}
http://www.ardendertat.com/2011/11/21/programming-interview-questions-17-search-unknown-length-array/
Given an integer array sorted in ascending order, write a function to search target in nums. If target exists, then return its index, otherwise return -1. However, the array size is unknown to you. You may only access the array using an ArrayReader interface, where ArrayReader.get(k) returns the element of the array at index k (0-indexed).
You may assume all integers in the array are less than 10000, and if you access the array out of bounds, ArrayReader.get will return 2147483647.
Example 1:
Input: array = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4
Example 2:
Input: array = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1
Note:
- You may assume that all elements in the array are unique.
- The value of each element in the array will be in the range [-9999, 9999].
Companies: Google
int search(const ArrayReader& reader, int target) {
int hi = 1;
while (reader.get(hi) < target) {
hi <<= 1;
}
int lo = hi >> 1;
while (lo <= hi) {
int mid = lo + (hi - lo) / 2;
int val = reader.get(mid);
if (val == target) {
return mid;
}
else if (val < target) {
lo = mid + 1;
}
else {
hi = mid - 1;
}
}
return -1;
}
http://www.ardendertat.com/2011/11/21/programming-interview-questions-17-search-unknown-length-array/