Jobdu-1530-最长不重复子串[解题代码] | Acm之家


九度-1530-最长不重复子串[解题代码] | Acm之家
最长不重复子串就是从一个字符串中找到一个连续子串,该子串中任何两个字符都不能相同,且该子串的长度是最大的。

03char str[10002];
04int has[26],cnt,ans,i,j,s;
05int main(){
06    while(~scanf("%s",str)){
07        ans=0,cnt=0,s=1;
08        memset(has,0,sizeof(has));
09        for( i=0; str[i]; i++){
10            if(has[str[i]-'a'] < s) cnt++;
11            else{
12                cnt=i-has[str[i]-'a'] + 1;
13                s=has[str[i]-'a'];
14            }
15            has[str[i]-'a'] = i+1;
16            if(cnt > ans) ans = cnt;
17        }
18        printf("%d\n",ans);
19    }
20    return 0;
21}
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