2D Peak Finding


Peak Finding: 1D and 2D
http://courses.csail.mit.edu/6.006/fall11/notes.shtml
http://courses.csail.mit.edu/6.006/fall10/notes.shtml

T(n) = T(n/2) + O(1)
Divide and Conquer
• Very powerful design tool:
– Divide input into multiple disjoint parts
– Conquer each of the parts separately 
(using recursive call)
• Occasionally, we need to combine results 
from different calls
1D
Consider the middle element of the array 
and compare with neighbors
– If A[n/2-1]>A[n/2]
then search for a peak among A[1]… A[n/2-1]
– Else, if A[n/2]<A[n/2+1]
then search for a peak among A[n/2]… A[n]
– Else A[n/2] is a peak! 
(since A[n/2-1]≤A[n/2] and A[n/2] ≥A[n/2+1] )

2D
Algorithm I:
– For each column j, find its global maximum B[j]
– Apply 1D peak finder to find a peak (say B[j]) 
of B[1...m]
O(n*m)

Algorithm II => O(nlogm)• Pick middle column ( j=m/2 )
• Find global maximum a=A[i,m/2] in that column
(and quit if m=1)
• Compare a to b=A[i,m/2-1] and c=A[i,m/2+1]
• If b>a 
then recurse on left columns
• Else, if c>a
then recurse on right columns
• Else a is a 2D peak!
Proof (by contradiction):

T(n,m)= T(n,m/2) + O(n) = O(nlogm)
T(n,n)= (n) + (n) +...+ (n) = (nlog m)
http://stackoverflow.com/questions/10531720/2d-peak-finding-algorithm-java-found-one-example-but-cant-code-it
https://github.com/fekberg/Algorithms/blob/master/Peak%20Finding/Peak%20Finding/Program.cs
    static void Peak(int[,] map, int left, int right)
    {
        // calculate middle column
        int column = (right + left) / 2;


        // get max row in column
        int arow = 0;
        for (int row = 0; row < map.GetLength(0); row++)
            if (map[row, column] > map[arow, column])
                arow = row;

        int a = map[arow, column];

        // get left value
        int b = 0;
        if (column - 1 >= left) b = map[arow, column - 1];
        // get right value
        int c = 0;
        if (column + 1 <= right) c = map[arow, column + 1];

        // if left is higher, recurse left
        if (b > a) Peak(map, left, column - 1);
        // else if right is higher, recurse right
        else if (c > a) Peak(map, column + 1, right);
        // else, peak
        else Console.WriteLine("Peak: " + arow + " " + column + " " + a);
    }

linear-time O(n + m)Reading only O(n + m) elements, reduce an array of n*m candidates to an array of n/2*m/2 candidates
http://stackoverflow.com/questions/23120300/2d-peak-finding-algorithm-in-on-worst-case-time
http://ideone.com/K3ggGm
  1. int findPeakLinearTime(int[][] arr){
  2. int rows = arr.length;
  3. int cols = arr[0].length;
  4. return kthLinearColumn(arr, 0, cols-1, 0, rows-1);
  5. }
  6.  
  7. // helper function that splits on the middle Column
  8. int kthLinearColumn(int[][] arr, int loCol, int hiCol, int loRow, int hiRow){
  9. if(loCol==hiCol){
  10. int max = arr[loRow][loCol];
  11. int foundRow = loRow;
  12. for(int row = loRow; row<=hiRow; row++){
  13. if(max < arr[row][loCol]){
  14. max = arr[row][loCol];
  15. foundRow = row;
  16. }
  17. }
  18. if(!correctPeak(arr, foundRow, loCol)){
  19. System.out.println("THIS PEAK IS WRONG");
  20. }
  21. return max;
  22. }
  23. int midCol = (loCol+hiCol)/2;
  24. int max = arr[loRow][loCol];
  25. for(int row=loRow; row<=hiRow; row++){
  26. max = Math.max(max, arr[row][midCol]);
  27. }
  28. boolean centralMax = true;
  29. boolean rightMax = false;
  30. boolean leftMax = false;
  31.  
  32. if(midCol-1 >= 0){
  33. for(int row = loRow; row<=hiRow; row++){
  34. if(arr[row][midCol-1] > max){
  35. max = arr[row][midCol-1];
  36. centralMax = false;
  37. leftMax = true;
  38. }
  39. }
  40. }
  41.  
  42. if(midCol+1 < M){
  43. for(int row=loRow; row<=hiRow; row++){
  44. if(arr[row][midCol+1] > max){
  45. max = arr[row][midCol+1];
  46. centralMax = false;
  47. leftMax = false;
  48. rightMax = true;
  49. }
  50. }
  51. }
  52.  
  53. if(centralMax) return max;
  54. if(rightMax) return kthLinearRow(arr, midCol+1, hiCol, loRow, hiRow);
  55. if(leftMax) return kthLinearRow(arr, loCol, midCol-1, loRow, hiRow);
  56. throw new RuntimeException("INCORRECT CODE");
  57. }
  58.  
  59. // helper function that splits on the middle
  60. int kthLinearRow(int[][] arr, int loCol, int hiCol, int loRow, int hiRow){
  61. if(loRow==hiRow){
  62. int ans = arr[loCol][loRow];
  63. int foundCol = loCol;
  64. for(int col=loCol; col<=hiCol; col++){
  65. if(arr[loRow][col] > ans){
  66. ans = arr[loRow][col];
  67. foundCol = col;
  68. }
  69. }
  70. if(!correctPeak(arr, loRow, foundCol)){
  71. System.out.println("THIS PEAK IS WRONG");
  72. }
  73. return ans;
  74. }
  75. boolean centralMax = true;
  76. boolean upperMax = false;
  77. boolean lowerMax = false;
  78.  
  79. int midRow = (loRow+hiRow)/2;
  80. int max = arr[midRow][loCol];
  81.  
  82. for(int col=loCol; col<=hiCol; col++){
  83. max = Math.max(max, arr[midRow][col]);
  84. }
  85.  
  86. if(midRow-1>=0){
  87. for(int col=loCol; col<=hiCol; col++){
  88. if(arr[midRow-1][col] > max){
  89. max = arr[midRow-1][col];
  90. upperMax = true;
  91. centralMax = false;
  92. }
  93. }
  94. }
  95.  
  96. if(midRow+1<N){
  97. for(int col=loCol; col<=hiCol; col++){
  98. if(arr[midRow+1][col] > max){
  99. max = arr[midRow+1][col];
  100. lowerMax = true;
  101. centralMax = false;
  102. upperMax = false;
  103. }
  104. }
  105. }
  106.  
  107. if(centralMax) return max;
  108. if(lowerMax) return kthLinearColumn(arr, loCol, hiCol, midRow+1, hiRow);
  109. if(upperMax) return kthLinearColumn(arr, loCol, hiCol, loRow, midRow-1);
  110. throw new RuntimeException("Incorrect code");
  111. }
  112.  
  113. int[][] randomArray(){
  114. int[][] arr = new int[N][M];
  115. for(int i=0; i<N; i++)
  116. for(int j=0; j<M; j++)
  117. arr[i][j] = (int)(Math.random()*1000000000);
  118. return arr;
  119. }
  120.  
  121. boolean correctPeak(int[][] arr, int row, int col){//Function that checks if arr[row][col] is a peak or not
  122. if(row-1>=0 && arr[row-1][col]>arr[row][col]) return false;
  123. if(row+1<N && arr[row+1][col]>arr[row][col]) return false;
  124. if(col-1>=0 && arr[row][col-1]>arr[row][col]) return false;
  125. if(col+1<M && arr[row][col+1]>arr[row][col]) return false;
  126. return true;
  127. }
  128. }

Code:
https://gist.github.com/tiraeth/1306602
http://www.geeksforgeeks.org/find-a-peak-in-a-given-array/
http://cresspahl.blogspot.com/2012/03/simple-algorithm-for-2d-peakfinding.html
http://stackoverflow.com/questions/9587173/algorithm-to-find-peaks-in-2d-array



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