Coding Recipies: TV remote


Coding Recipies: TV remote
Gaurav has fractured his leg in a bicycle accident.He keeps himself busy by watching television on his Tata Sky DTH. While watching the television, one day he decided to play a small game, where
he has to identify the minimum number of clicks required to surf a given set of channels in a

sequence.
WAP with given instructions:

Instructions

There are 13 buttons on his remote: 10 buttons for the numbers (0-9), an "Up Channel" button,
a "Down Channel" button, and a "Back" button:

● The number buttons allow you to jump directly to a specific channel. (Ex: to go to
channel 63 by typing "6", "3".)
● The "Up Channel" button increments the current channel to the next higher viewable
channel, unless the current channel is the highest viewable channel, in which case it
rolls over to the lowest viewable channel.
● The "Down Channel" button decrements to the next lower viewable channel, unless the
current channel is the lowest viewable channel, in which case it rolls over to the highest
viewable channel.
● The "Back" button reverts to whatever channel was on the television before the current
channel. (Ex: If channel 1 is viewed, then channel 100, then when Back is pressed, the
television will go to channel 1.)

Gaurav can get from one channel to the next in one of the two ways:
● Clicking any combination of "Up Channel", "Down Channel", and "Back" buttons.
● Keying in the numbers to the channel. Gaurav will never combine "Back" and number
buttons when moving from one channel to the next.

Gaurav's parents have set some parental control on some channels on Gaurav's television.
These channels are not viewable, so they are skipped by the "Up Channel" and "Down
Channel" buttons.

Given a list of channels to view, the lowest channel, the highest channel, and a list of blocked
channels, your program should return the minimum number of clicks necessary to get
through all the shows that Gaurav would like to watch.

Constraints 
● The sequence that Gaurav must view contains between 1 and 50 elements, inclusive. All 
channels in this sequence are not in the blocked list and are between lowest channel 
and highest channel, inclusive. 
 class TVRemote {
    private int BackChannel = 0;
    private List<Integer> channels;
    private int currentIndex = 0;
    private int clicks = 0;
    private int totalChannels;
    public TVRemote(int low, int high, int[] blocked, int[] view) {
        channels = new ArrayList<Integer>(high - low);
        for (int i = low; i <= high; i++)
            channels.add(i);
        for (Integer o : blocked)
            channels.remove(o);
        totalChannels = channels.size();
    }
    public int solve(int low, int high, int[] view) {
        for (int i = 0; i < view.length; i++) {
            int toBeViewedChannel = view[i];
            int toBeViewedIndex = getIndex(toBeViewedChannel);
            int diff = getDiff(currentIndex, toBeViewedIndex);
            int absDiff = Math.abs(diff);
            int numDigits = String.valueOf(toBeViewedChannel).length();
            if (diff == 0) // same channel
                continue;
            else if (BackChannel == toBeViewedIndex) // when back is to be
                                                        // pressed
                backPressed(toBeViewedIndex);
            else if (absDiff > numDigits) // when number of digits are less than
                                            // displacement
                goToChannel(toBeViewedChannel, toBeViewedIndex, numDigits);
            else // when displacement is less than number of digits
            {
                for (int j = 0; j < absDiff; j++) {
                    if (diff < 0)
                        downPressed();
                    else
                        upPressed();
                }
            }
        }
        return clicks;
    }
    /**
     * Get the displacement between start Index to End Index in an Array
     */
    private int getDiff(int start, int end) {
        int diff1 = Math.abs(end - start);
        int diff2 = Math.abs(totalChannels - diff1);
        if(start < end)
            return diff1 < diff2 ? diff1 : -diff2;
        else
            return diff1 < diff2 ? -diff1 : diff2;
    }
    /**
     * @param channel
     *            : given the channel
     * @return : returns the index of the channel
     */
    private int getIndex(int channel) {
        for (int index = 0; index < totalChannels; index++)
            if (channel == channels.get(index))
                return index;
        return 0;
    }
    private void goToChannel(int toBeViewedChannel, int toBeViewedIndex,
            int numDigits) {
        BackChannel = currentIndex;
        currentIndex = toBeViewedIndex;
        for (int j = 0; j < numDigits; j++)
            clicks++;
    }
    /**
     * Up Button is pressed
     */
    private void upPressed() {
        BackChannel = currentIndex;
        if (currentIndex == totalChannels - 1)
            currentIndex = 0;
        else
            currentIndex++;
        clicks++;
    }
    /**
     * Down Button is Pressed
     */
    private void downPressed() {
        BackChannel = currentIndex;
        if (currentIndex == 0)
            currentIndex = totalChannels - 1;
        else
            currentIndex--;
        clicks++;
    }
    /**
     * Back BUtton is pressed
     * @param toBeViewedIndex
     */
    private void backPressed(int toBeViewedIndex) {
        BackChannel = currentIndex;
        currentIndex = toBeViewedIndex;
        clicks++;
    }
}
Related: http://massivealgorithms.blogspot.com/2014/07/avid-tv-watcher-programming-interviews.html
Read full article from Coding Recipies: TV remote

Labels

LeetCode (1432) GeeksforGeeks (1122) LeetCode - Review (1067) Review (882) Algorithm (668) to-do (609) Classic Algorithm (270) Google Interview (237) Classic Interview (222) Dynamic Programming (220) DP (186) Bit Algorithms (145) POJ (141) Math (137) Tree (132) LeetCode - Phone (129) EPI (122) Cracking Coding Interview (119) DFS (115) Difficult Algorithm (115) Lintcode (115) Different Solutions (110) Smart Algorithm (104) Binary Search (96) BFS (91) HackerRank (90) Binary Tree (86) Hard (79) Two Pointers (78) Stack (76) Company-Facebook (75) BST (72) Graph Algorithm (72) Time Complexity (69) Greedy Algorithm (68) Interval (63) Company - Google (62) Geometry Algorithm (61) Interview Corner (61) LeetCode - Extended (61) Union-Find (60) Trie (58) Advanced Data Structure (56) List (56) Priority Queue (53) Codility (52) ComProGuide (50) LeetCode Hard (50) Matrix (50) Bisection (48) Segment Tree (48) Sliding Window (48) USACO (46) Space Optimization (45) Company-Airbnb (41) Greedy (41) Mathematical Algorithm (41) Tree - Post-Order (41) ACM-ICPC (40) Algorithm Interview (40) Data Structure Design (40) Graph (40) Backtracking (39) Data Structure (39) Jobdu (39) Random (39) Codeforces (38) Knapsack (38) LeetCode - DP (38) Recursive Algorithm (38) String Algorithm (38) TopCoder (38) Sort (37) Introduction to Algorithms (36) Pre-Sort (36) Beauty of Programming (35) Must Known (34) Binary Search Tree (33) Follow Up (33) prismoskills (33) Palindrome (32) Permutation (31) Array (30) Google Code Jam (30) HDU (30) Array O(N) (29) Logic Thinking (29) Monotonic Stack (29) Puzzles (29) Code - Detail (27) Company-Zenefits (27) Microsoft 100 - July (27) Queue (27) Binary Indexed Trees (26) TreeMap (26) to-do-must (26) 1point3acres (25) GeeksQuiz (25) Merge Sort (25) Reverse Thinking (25) hihocoder (25) Company - LinkedIn (24) Hash (24) High Frequency (24) Summary (24) Divide and Conquer (23) Proof (23) Game Theory (22) Topological Sort (22) Lintcode - Review (21) Tree - Modification (21) Algorithm Game (20) CareerCup (20) Company - Twitter (20) DFS + Review (20) DP - Relation (20) Brain Teaser (19) DP - Tree (19) Left and Right Array (19) O(N) (19) Sweep Line (19) UVA (19) DP - Bit Masking (18) LeetCode - Thinking (18) KMP (17) LeetCode - TODO (17) Probabilities (17) Simulation (17) String Search (17) Codercareer (16) Company-Uber (16) Iterator (16) Number (16) O(1) Space (16) Shortest Path (16) itint5 (16) DFS+Cache (15) Dijkstra (15) Euclidean GCD (15) Heap (15) LeetCode - Hard (15) Majority (15) Number Theory (15) Rolling Hash (15) Tree Traversal (15) Brute Force (14) Bucket Sort (14) DP - Knapsack (14) DP - Probability (14) Difficult (14) Fast Power Algorithm (14) Pattern (14) Prefix Sum (14) TreeSet (14) Algorithm Videos (13) Amazon Interview (13) Basic Algorithm (13) Codechef (13) Combination (13) Computational Geometry (13) DP - Digit (13) LCA (13) LeetCode - DFS (13) Linked List (13) Long Increasing Sequence(LIS) (13) Math-Divisible (13) Reservoir Sampling (13) mitbbs (13) Algorithm - How To (12) Company - Microsoft (12) DP - Interval (12) DP - Multiple Relation (12) DP - Relation Optimization (12) LeetCode - Classic (12) Level Order Traversal (12) Prime (12) Pruning (12) Reconstruct Tree (12) Thinking (12) X Sum (12) AOJ (11) Bit Mask (11) Company-Snapchat (11) DP - Space Optimization (11) Dequeue (11) Graph DFS (11) MinMax (11) Miscs (11) Princeton (11) Quick Sort (11) Stack - Tree (11) 尺取法 (11) 挑战程序设计竞赛 (11) Coin Change (10) DFS+Backtracking (10) Facebook Hacker Cup (10) Fast Slow Pointers (10) HackerRank Easy (10) Interval Tree (10) Limited Range (10) Matrix - Traverse (10) Monotone Queue (10) SPOJ (10) Starting Point (10) States (10) Stock (10) Theory (10) Tutorialhorizon (10) Kadane - Extended (9) Mathblog (9) Max-Min Flow (9) Maze (9) Median (9) O(32N) (9) Quick Select (9) Stack Overflow (9) System Design (9) Tree - Conversion (9) Use XOR (9) Book Notes (8) Company-Amazon (8) DFS+BFS (8) DP - States (8) Expression (8) Longest Common Subsequence(LCS) (8) One Pass (8) Quadtrees (8) Traversal Once (8) Trie - Suffix (8) 穷竭搜索 (8) Algorithm Problem List (7) All Sub (7) Catalan Number (7) Cycle (7) DP - Cases (7) Facebook Interview (7) Fibonacci Numbers (7) Flood fill (7) Game Nim (7) Graph BFS (7) HackerRank Difficult (7) Hackerearth (7) Inversion (7) Kadane’s Algorithm (7) Manacher (7) Morris Traversal (7) Multiple Data Structures (7) Normalized Key (7) O(XN) (7) Radix Sort (7) Recursion (7) Sampling (7) Suffix Array (7) Tech-Queries (7) Tree - Serialization (7) Tree DP (7) Trie - Bit (7) 蓝桥杯 (7) Algorithm - Brain Teaser (6) BFS - Priority Queue (6) BFS - Unusual (6) Classic Data Structure Impl (6) DP - 2D (6) DP - Monotone Queue (6) DP - Unusual (6) DP-Space Optimization (6) Dutch Flag (6) How To (6) Interviewstreet (6) Knapsack - MultiplePack (6) Local MinMax (6) MST (6) Minimum Spanning Tree (6) Number - Reach (6) Parentheses (6) Pre-Sum (6) Probability (6) Programming Pearls (6) Rabin-Karp (6) Reverse (6) Scan from right (6) Schedule (6) Stream (6) Subset Sum (6) TSP (6) Xpost (6) n00tc0d3r (6) reddit (6) AI (5) Abbreviation (5) Anagram (5) Art Of Programming-July (5) Assumption (5) Bellman Ford (5) Big Data (5) Code - Solid (5) Code Kata (5) Codility-lessons (5) Coding (5) Company - WMware (5) Convex Hull (5) Crazyforcode (5) DFS - Multiple (5) DFS+DP (5) DP - Multi-Dimension (5) DP-Multiple Relation (5) Eulerian Cycle (5) Graph - Unusual (5) Graph Cycle (5) Hash Strategy (5) Immutability (5) Java (5) LogN (5) Manhattan Distance (5) Matrix Chain Multiplication (5) N Queens (5) Pre-Sort: Index (5) Quick Partition (5) Quora (5) Randomized Algorithms (5) Resources (5) Robot (5) SPFA(Shortest Path Faster Algorithm) (5) Shuffle (5) Sieve of Eratosthenes (5) Strongly Connected Components (5) Subarray Sum (5) Sudoku (5) Suffix Tree (5) Swap (5) Threaded (5) Tree - Creation (5) Warshall Floyd (5) Word Search (5) jiuzhang (5)

Popular Posts