Jobdu -1340-小A的计算器[进制转换] | Acm之家


九度-1340-小A的计算器[进制转换] | Acm之家
 以往的操作系统内部的数据表示都是二进制方式,小A新写了一个操作系统,系统内部的数据表示为26进制,其中0-25分别由a-z表示。
现在小A要在这个操作系统上实现一个计算器,这个计算器要能实现26进制数的加法运算。你能帮小A实现这个计算器吗?
          while(N--){
14 
15                     memset(sum,0,16 * sizeof(int));
16                     scanf("%s%s",a,b);
17                     la = strlen(a);
18                     lb = strlen(b);
19                     for(i=la-1,j=lb-1,k=0;i>=0 && j >= 0;--i,--j){
20                                            sum[k++] = a[i]-'a' + b[j] - 'a';
21 
22                     }
23                     if(i<0 && j>=0){
24                            for(;j>=0;j--)
25                            sum[k++] = b[j] - 'a';
26                    }
27                    if(i>=0 && j<0){
28                            for(;i>=0;i--)
29                            sum[k++] = a[i] - 'a';
30                    }
31                    for(i=0;i<k;i++){
32                                sum[i+1] = sum[i+1] + sum[i] / 26;
33                                sum[i] = sum[i] % 26;
34                    }
35                    for(i=k+1;i>=0;i--){
36                                    if(sum[i] != 0)
37                                              break;
38                    }
39                    if(i== -1)
40                           printf("a");
41                    for(;i>=0;i--)
42                    printf("%c",'a'+ sum[i]);
43 
44                    printf("\n");
45        }  
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