Print string of odd length in 'X' format - GeeksforGeeks

Print string of odd length in 'X' format - GeeksforGeeks
Given a string of odd length, print the string X format.

Input: 12345
Output:
1       5
  2   4
    3
  2   4
1       5 

The idea is to use two variables in a single loop, the first variable ‘i’ goes from left to right and second variables ‘j’ goes from right to left. The upper part of Cross (or X) is printed before they meet. The central character is printed when they meet and lower parted is printed after they cross each other. In the upper part str[i] is printed before str[j] and in the lower part, str[j] is printed before str[i].

// Function to print given string in cross pattern

// Length of string must be odd

void printPattern(string str)

{

    int len = str.length();

 

    // i goes from 0 to len and j goes from len-1 to 0

    for (int i=0,j=len-1; i<=len,j>=0; i++,j--)

    {

        // To print the upper part. This loop runs

        // til middle point of string (i and j become

        // same

        if (i<j)

        {

            // Print i spaces

            for (int x=0; x<i; x++)

                cout << " ";

 

            // Print i'th character

            cout << str[i];

 

            // Print j-i-1 spaces

            for (int x=0; x<j-i-1; x++)

                cout << " ";

 

            // Print j'th character

            cout << str[j] << endl;

        }

 

        // To print center point

        if (i==j)

        {

            // Print i spaces

            for (int x=0; x<i; x++)

                cout << " ";

 

            // Print middle character

            cout << str[i] << endl;

        }

 

        // To print lower part

        else if (i>j)

        {

            // Print j spances

            for (int x = j-1; x>=0; x--)

                cout << " ";

 

            // Print j'th character

            cout << str[j];

 

            // Print i-j-1 spaces

            for (int x=0; x<i-j-1; x++)

                cout << " ";

 

            // Print i'h character

            cout << str[i] << endl;

        }

    }

}

https://ideone.com/l8wyjY

1. int main()
2. {
3. char str[100];
4. int i,j,l;
5. cin>>str;
6. l=strlen(str);
7. for(i=0;i<l;i++)
8. {
9. for(j=0;j<l;j++)
10. {
11. if(i==j||(i+j==l-1))
12. cout<<str[j];
13. else
14. cout<<" ";
15. }
16. cout<<"\n";
17. }
18. return 0;
19. }

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