Jobdu-1342-寻找最长合法括号序列II(25分)[解题代码] | Acm之家


九度-1342-寻找最长合法括号序列II(25分)[解题代码] | Acm之家
假如给你一个由'('和')'组成的一个随机的括号序列,当然,这个括号序列肯定不能保证是左右括号匹配的,所以给你的任务便是去掉其中的一些括号,使得剩下的括号序列能够左右括号匹配且长度最长,即最长的合法括号序列。
http://blog.csdn.net/u013027996/article/details/18729561
  1.     public static void main(String[] args) throws Exception {  
  2.         Scanner scanner = new Scanner(System.in);  
  3.         while (scanner.hasNext()) {  
  4.             String a = scanner.next();  
  5.             char array[] = a.toCharArray();  
  6.             int num = 0;  
  7.             Stack<Character> stack = new Stack<Character>();  
  8.             for (int i = 0; i < array.length; i++) {  
  9.                 if (array[i] == '(') {  
  10.                     stack.push(array[i]);  
  11.                 }else if (array[i] == ')' && !stack.isEmpty()){  
  12.                     stack.pop();  
  13.                     num += 2;  
  14.                 }  
  15.             }  
  16.             System.out.println(num);  
  17.         }  
  18.     }  

05    while (scanf("%s",s) != EOF) {
06        l = ans = 0;
07        for(i=0; s[i]; i++){
08            if(s[i] == '('){
09                l++;
10            }else{
11                if(l){
12                    ans += 2;
13                    l--;
14                }
15            }
16        }
17        printf("%d\n", ans);
18    }
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