AOJ 0118 Property Distribution《挑战程序设计竞赛(第2版)》练习题答案 � 码农场


2.1 最基础的"穷竭搜索" 深度优先搜索 AOJ 0118 Property Distribution
题意:
在H * W的矩形果园里有苹果、梨、蜜柑三种果树, 相邻(上下左右)的同种果树属于同一个区域,给出果园的果树分布,求总共有多少个区域。 (原题的样图中苹果为リ,梨为カ,蜜柑为ミ, 图中共10个区域)
输入:
多组数据,每组数据第一行为两个整数H,W(H <= 100, W <= 100), H =0 且 W = 0代表输入结束。以下H行W列表示果园的果树分布, 苹果是@,梨是#, 蜜柑是*。
输出:
对于每组数据,输出其区域的个数。
char farm[MAX_W][MAX_H];
int W, H;
const int direction[4][2] = {
    { -1, 0 },
    { 1, 0 },
    { 0, -1 },
    { 0, 1 },
};
void dfs(const int& x, const int& y, const char tree)
{
    farm[x][y] = 'x';
    for (int i = 0; i < 4; ++i)
    {
        int nx = x + direction[i][0];
        int ny = y + direction[i][1];
        if (nx >= 0 && nx < W && ny >= 0 && ny < H && farm[nx][ny] == tree)
        {
            dfs(nx, ny, tree);
        }
    }
}
int main(int argc, char *argv[])
{
    while (cin >> H >> W, W > 0)
    {
        int res = 0;
        int x, y;
        for (y = 0; y < H; ++y)
        {
            for (x = 0; x < W; ++x)
            {
                cin >> farm[x][y];
            }
        }
        for (y = 0; y < H; ++y)
        {
            for (x = 0; x < W; ++x)
            {
                if (farm[x][y] != 'x')
                {
                    dfs(x, y, farm[x][y]);
                    ++res;
                }
            }
        }
        cout << res << endl;
    }
    return 0;
}
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