Given an an unsorted array, sort the given array. You are allowed to do only following operation on array.
flip(arr, i): Reverse array from 0 to i
If we apply the same algorithm here, the time taken will be O(n^2) because the algorithm calls findMax() in a loop and find findMax() takes O(n) time even on this hypothetical machine.
We can use insertion sort that uses binary search. The idea is to run a loop from second element to last element (from i = 1 to n-1), and one by one insert arr[i] in arr[0..i-1] (like standard insertion sort algorithm). When we insert an element arr[i], we can use binary search to find position of arr[i] in O(Logi) time. Once we have the position, we can use some flip operations to put arr[i] at its new place. Following are abstract steps.
// Standard Insertion Sort Loop that starts from second element
for (i=1; i < n; i++) ----> O(n)
{
int key = arr[i];
// Find index of ceiling of arr[i] in arr[0..i-1] using binary search
j = celiSearch(arr, key, 0, i-1); ----> O(logn) (See this)
// Apply some flip operations to put arr[i] at correct place
}
Since flip operation takes O(1) on given hypothetical machine, total running time of above algorithm is O(nlogn).
ceilSearch() actually returns the index of the smallest element which is greater than arr[i] in arr[0..i-1]. If there is no such element, it returns -1. Let the returned value be j. If j is -1, then we don’t need to do anything as arr[i] is already the greatest element among arr[0..i].
Let i be 6 and current array be {12, 15, 18, 30, 35, 40, 20, 6, 90, 80}. To put 20 at its new place, the array should be changed to {12, 15, 18, 20, 30, 35, 40, 6, 90, 80}. We apply following steps to put 20 at its new place.
1) Find j using ceilSearch (In the above example j is 3).
2) flip(arr, j-1) (array becomes {18, 15, 12, 30, 35, 40, 20, 6, 90, 80})
3) flip(arr, i-1); (array becomes {40, 35, 30, 12, 15, 18, 20, 6, 90, 80})
4) flip(arr, i); (array becomes {20, 18, 15, 12, 30, 35, 40, 6, 90, 80})
5) flip(arr, j); (array becomes {12, 15, 18, 20, 30, 35, 40, 6, 90, 80})
2) flip(arr, j-1) (array becomes {18, 15, 12, 30, 35, 40, 20, 6, 90, 80})
3) flip(arr, i-1); (array becomes {40, 35, 30, 12, 15, 18, 20, 6, 90, 80})
4) flip(arr, i); (array becomes {20, 18, 15, 12, 30, 35, 40, 6, 90, 80})
5) flip(arr, j); (array becomes {12, 15, 18, 20, 30, 35, 40, 6, 90, 80})
/* A Binary Search based function to get index of ceiling of x in arr[low..high] */int ceilSearch(int arr[], int low, int high, int x){ int mid; /* If x is smaller than or equal to the first element, then return the first element */ if(x <= arr[low]) return low; /* If x is greater than the last element, then return -1 */ if(x > arr[high]) return -1; /* get the index of middle element of arr[low..high]*/ mid = (low + high)/2; /* low + (high – low)/2 */ /* If x is same as middle element, then return mid */ if(arr[mid] == x) return mid; /* If x is greater than arr[mid], then either arr[mid + 1] is ceiling of x, or ceiling lies in arr[mid+1...high] */ if(arr[mid] < x) { if(mid + 1 <= high && x <= arr[mid+1]) return mid + 1; else return ceilSearch(arr, mid+1, high, x); } /* If x is smaller than arr[mid], then either arr[mid] is ceiling of x or ceiling lies in arr[mid-1...high] */ if (mid - 1 >= low && x > arr[mid-1]) return mid; else return ceilSearch(arr, low, mid - 1, x);}/* Reverses arr[0..i] */void flip(int arr[], int i){ int temp, start = 0; while (start < i) { temp = arr[start]; arr[start] = arr[i]; arr[i] = temp; start++; i--; }}/* Function to sort an array using insertion sort, binary search and flip */void insertionSort(int arr[], int size){ int i, j; // Start from the second element and one by one insert arr[i] // in already sorted arr[0..i-1] for(i = 1; i < size; i++) { // Find the smallest element in arr[0..i-1] which is also greater than // or equal to arr[i] int j = ceilSearch(arr, 0, i-1, arr[i]); // Check if there was no element greater than arr[i] if (j != -1) { // Put arr[i] before arr[j] using following four flip operations flip(arr, j-1); flip(arr, i-1); flip(arr, i); flip(arr, j); } }} insertionSort(arr, n);Read full article from A Pancake Sorting Problem | GeeksforGeeks
