Solution to Distinct by codility | Code Says


Solution to Distinct by codility | Code Says
Write a function
int solution(int A[], int N);
that, given a zero-indexed array A consisting of N integers, returns the number of distinct values in array A.
Assume that:
  • N is an integer within the range [0..100,000];
  • each element of array A is an integer within the range [−1,000,000..1,000,000].
For example, given array A consisting of six elements such that:
A[0] = 2    A[1] = 1    A[2] = 1
A[3] = 2    A[4] = 3    A[5] = 1
the function should return 3, because there are 3 distinct values appearing in array A, namely 1, 2 and 3.
Pre-sort - O(1) space, nlogn time:
def solution(A):
    if len(A) == 0:
        distinct = 0
    else:
        distinct = 1
 
        A.sort()
        for index in xrange(1, len(A)):
            if A[index] == A[index-1]:
                # The same element as the previous one
                continue
            else:
                # A new element
                distinct += 1
 
    return distinct

Hashset:
3
4
5
Set set = new HashSet();
for (int i : A) {      
set.add(i);        
}                      
return set.size();

JDK 8 lambda stream:
Set<Integer> result=IntStream.of(A).boxed().collect(Collectors.toSet());
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