LeetCode 223 - Rectangle Area


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LeetCode – Rectangle Area (Java)
Find the total area covered by two rectilinear rectangles in a 2D plane. Each rectangle is defined by its bottom left corner and top right corner coordinates.

http://www.cnblogs.com/easonliu/p/4560596.html
因为只有两个矩形,所以直接算结果 = 两个矩形的面积 - 相交的面积。估计下一道题就会是求多个矩形的覆盖面积了吧。
https://gist.github.com/gcrfelix/bbd71a084a06c23f2384
public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
    if(C<E||G<||  D<F || H<B)
        return (G-E)*(H-F) + (C-A)*(D-B);
 
    int right = Math.min(C,G);
    int left = Math.max(A,E);
    int top = Math.min(H,D);
    int bottom = Math.max(F,B);
 
    return (G-E)*(H-F) + (C-A)*(D-B) - (right-left)*(top-bottom);
}

    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int left = Math.max(A, E);
        int right = Math.min(C, G);
        int bottom = Math.max(B, F);
        int top = Math.min(D, H);
     
        int overlap = 0;
        if(left < right && bottom < top) {
            overlap = (right-left)*(top-bottom);
        }
        int area1 = (C-A)*(D-B);
        int area2 = (G-E)*(H-F);
        return area1 + area2 - overlap;
    }
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