Binary Insertion Sort - GeeksQuiz

Binary Insertion Sort - GeeksQuiz
We can use binary search to reduce the number of comparisons in normal insertion sort. Binary Insertion Sort find use binary search to find the proper location to insert the selected item at each iteration.
In normal insertion, sort it takes O(i) (at ith iteration) in worst case. we can reduce it to O(logi) by using binary search.

// A binary search based function to find the position

// where item should be inserted in a[low..high]

int binarySearch(int a[], int item, int low, int high)

{

    if (high <= low)

        return (item > a[low])?  (low + 1): low;

 

    int mid = (low + high)/2;

 

    if(item == a[mid])

        return mid+1;

 

    if(item > a[mid])

        return binarySearch(a, item, mid+1, high);

    return binarySearch(a, item, low, mid-1);

}

 

// Function to sort an array a[] of size 'n'

void insertionSort(int a[], int n)

{

    int i, loc, j, k, selected;

 

    for (i = 1; i < n; ++i)

    {

        j = i - 1;

        selected = a[i];

 

        // find location where selected sould be inseretd

        loc = binarySearch(a, selected, 0, j);

 

        // Move all elements after location to create space

        while (j >= loc)

        {

            a[j+1] = a[j];

            j--;

        }

        a[j+1] = selected;

    }

}

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