Find the k-th element - EPI


Find the k-th largest element KThLargestElement.java

  public static int findKthLargest(List<Integer> A, int k) {
    int left = 0, right = A.size() - 1;

    Random r = new Random();
    while (left <= right) {
      // Generates a random int in [left, right].
      int p = partition(left, right, r.nextInt(right - left + 1) + left, A);
      if (p == k - 1) {
        return A.get(p);
      } else if (p > k - 1) {
        right = p - 1;
      } else { // p < k - 1.
        left = p + 1;
      }
    }
    // @exclude
    throw new RuntimeException("no k-th node in array A");
    // @include
  }

  // Partitions A according pivot, returns its index after partition.
  private static int partition(int left, int right, int pivot,
                               List<Integer> A) {
    int pivotValue = A.get(pivot);
    int largerIndex = left;

    Collections.swap(A, pivot, right);
    for (int i = left; i < right; ++i) {
      if (A.get(i) > pivotValue) {
        Collections.swap(A, i, largerIndex++);
      }
    }
    Collections.swap(A, right, largerIndex);
    return largerIndex;
  }

Find the k-th largest element---large n, small $k$

KthLargestElementLargeN.java
  private static class Greater<T extends Comparable<T>> implements
      Comparator<T> {
    @Override
    public int compare(T o1, T o2) {
      return o2.compareTo(o1);
    }
  public static int findKthLargestUnknownLength(InputStream sin, int k) {
    List<Integer> M = new ArrayList<>();
    Scanner s = new Scanner(sin);
    while (s.hasNextInt()) {
      int x = s.nextInt();
      M.add(x);
      if (M.size() == (k * 2) - 1) {
        // Keeps the k largest elements and discard the small ones.
        nthElement(M, k - 1, new Greater<Integer>());
        M = new ArrayList<>(M.subList(0, k));
      }
    }
    nthElement(M, k - 1, new Greater<Integer>());
    return M.get(k - 1); // return the k-th largest one.
  }

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