微策略2012年校园招聘笔试题-棋盘寻宝扩展


http://www.acmerblog.com/blog-1243.html
现在有一个8*8的棋盘,上面放着64个不同价值的礼物,每个小的棋盘上面放置一个礼物(礼物的价值大于0小于100),一个人初始位置在棋盘的左上角,每次他只能向下或向右移动一步,并拿走对应棋盘上的礼物,结束位置在棋盘的右下角。从棋盘的左上角移动到右下角的时候的,每次他只能向下或向右移动一步,并拿走对应棋盘上的礼物,但是拿到的所有的礼物的价值之和不大于一个限定值limit,请设计一个算法请实现,使其能够获得不超过限制值limit的最大价值的礼物。 
加了限制,这时只能考虑有情况了。这里使用dfs求解,加上剪枝:if (sum > limit) return;
02int map[8][8], i, j, ans, limit;
03void f(int x, int y, int sum) {
04    sum += map[x][y];
05    if (sum > limit)
06        return;
07    if (x == 7 && y == 7 && sum > ans)
08        ans = sum;
09    if (x < 7)
10        f(x + 1, y, sum);
11    if (y < 7)
12        f(x, y + 1, sum);
13}
14 
15int main() {
16    while(~scanf("%d",&limit)) {
17        ans = 0;
18        for(i=0; i<8; i++) {
19            for(j=0; j<8; j++) {
20                scanf("%d",&map[i][j]);
21            }
22        }
23        f(0,0,0);
24        if(ans > 0)
25        printf("%d\n",ans);
26        else puts("-1");
27    }
28    return 0;
29}

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