Some interesting shortest path questions | Set 1 | GeeksforGeeks
Question 1: Given a directed weighted graph. You are also given the shortest path from a source vertex ‘s’ to a destination vertex ‘t’. If weight of every edge is increased by 10 units, does the shortest path remain same in the modified graph?
The shortest path may change. The reason is, there may be different number of edges in different paths from s to t. For example, let shortest path be of weight 15 and has 5 edges. Let there be another path with 2 edges and total weight 25.
Question 2: This is similar to above question. Does the shortest path change when weights of all edges are multiplied by 10?
If we multiply all edge weights by 10, the shortest path doesn’t change. The reason is simple, weights of all paths from s to t get multiplied by same amount. The number of edges on a path doesn’t matter. It is like changing unit of weights.
Read full article from Some interesting shortest path questions | Set 1 | GeeksforGeeks
Question 1: Given a directed weighted graph. You are also given the shortest path from a source vertex ‘s’ to a destination vertex ‘t’. If weight of every edge is increased by 10 units, does the shortest path remain same in the modified graph?
The shortest path may change. The reason is, there may be different number of edges in different paths from s to t. For example, let shortest path be of weight 15 and has 5 edges. Let there be another path with 2 edges and total weight 25.
Question 2: This is similar to above question. Does the shortest path change when weights of all edges are multiplied by 10?
If we multiply all edge weights by 10, the shortest path doesn’t change. The reason is simple, weights of all paths from s to t get multiplied by same amount. The number of edges on a path doesn’t matter. It is like changing unit of weights.
Question 3: Given a directed graph where every edge has weight as either 1 or 2, find the shortest path from a given source vertex ‘s’ to a given destination vertex ‘t’. Expected time complexity is O(V+E).
If we apply Dijkstra’s shortest path algorithm, we can get a shortest path in O(E + VLogV) time. How to do it in O(V+E) time? The idea is to use BFS . One important observation about BFS is, the path used in BFS always has least number of edges between any two vertices. So if all edges are of same weight, we can use BFS to find the shortest path. For this problem, we can modify the graph and split all edges of weight 2 into two edges of weight 1 each. In the modified graph, we can use BFS to find the shortest path. How is this approach O(V+E)? In worst case, all edges are of weight 2 and we need to do O(E) operations to split all edges, so the time complexity becomes O(E) + O(V+E) which is O(V+E).
If we apply Dijkstra’s shortest path algorithm, we can get a shortest path in O(E + VLogV) time. How to do it in O(V+E) time? The idea is to use BFS . One important observation about BFS is, the path used in BFS always has least number of edges between any two vertices. So if all edges are of same weight, we can use BFS to find the shortest path. For this problem, we can modify the graph and split all edges of weight 2 into two edges of weight 1 each. In the modified graph, we can use BFS to find the shortest path. How is this approach O(V+E)? In worst case, all edges are of weight 2 and we need to do O(E) operations to split all edges, so the time complexity becomes O(E) + O(V+E) which is O(V+E).
Question 4: Given a directed acyclic weighted graph, how to find the shortest path from a source s to a destination t in O(V+E) time?
See: Shortest Path in Directed Acyclic Graph
See: Shortest Path in Directed Acyclic Graph
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