Given two bit sequences as strings, write a function to return the addition of the two sequences. Bit strings can be of different lengths also.
Since sizes of two strings may be different, we first make the size of smaller string equal to that of bigger string by adding leading 0s.
In every iteration, we need to sum 3 bits: 2 bits of 2 given strings and carry. The sum bit will be 1 if, either all of the 3 bits are set or one of them is set. So we can do XOR of all bits to find the sum bit. How to find carry – carry will be 1 if any of the two bits is set. So we can find carry by taking OR of all pairs
1. Make them equal sized by adding 0s at the begining of smaller string.
2. Perform bit addition
…..Boolean expression for adding 3 bits a, b, c
…..Sum = a XOR b XOR c
…..Carry = (a AND b) OR ( b AND c ) OR ( c AND a )
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Since sizes of two strings may be different, we first make the size of smaller string equal to that of bigger string by adding leading 0s.
In every iteration, we need to sum 3 bits: 2 bits of 2 given strings and carry. The sum bit will be 1 if, either all of the 3 bits are set or one of them is set. So we can do XOR of all bits to find the sum bit. How to find carry – carry will be 1 if any of the two bits is set. So we can find carry by taking OR of all pairs
1. Make them equal sized by adding 0s at the begining of smaller string.
2. Perform bit addition
…..Boolean expression for adding 3 bits a, b, c
…..Sum = a XOR b XOR c
…..Carry = (a AND b) OR ( b AND c ) OR ( c AND a )
int makeEqualLength(string &str1, string &str2){ int len1 = str1.size(); int len2 = str2.size(); if (len1 < len2) { for (int i = 0 ; i < len2 - len1 ; i++) str1 = '0' + str1; return len2; } else if (len1 > len2) { for (int i = 0 ; i < len1 - len2 ; i++) str2 = '0' + str2; } return len1; // If len1 >= len2}// The main function that adds two bit sequences and returns the additionstring addBitStrings( string first, string second ){ string result; // To store the sum bits // make the lengths same before adding int length = makeEqualLength(first, second); int carry = 0; // Initialize carry // Add all bits one by one for (int i = length-1 ; i >= 0 ; i--) { int firstBit = first.at(i) - '0'; int secondBit = second.at(i) - '0'; // boolean expression for sum of 3 bits int sum = (firstBit ^ secondBit ^ carry)+'0'; result = (char)sum + result; // boolean expression for 3-bit addition carry = (firstBit & secondBit) | (secondBit & carry) | (firstBit & carry); } // if overflow, then add a leading 1 if (carry) result = '1' + result; return result;}