Write a C program to find the parity of an unsigned integer | GeeksforGeeks


Write a C program to find the parity of an unsigned integer | GeeksforGeeks
Parity: Parity of a number refers to whether it contains an odd or even number of 1-bits. The number has “odd parity”, if it contains odd number of 1-bits and is “even parity” if it contains even number of 1-bits.
We don't need the count of odd or even bit, just invert between true/false when hit one bit set.
1. Initialize parity = 0
2. Loop while n != 0      
      a. Invert parity 
             parity = !parity
      b. Unset rightmost set bit
             n = n & (n-1)
3. return parity
bool getParity(unsigned int n)
{
    bool parity = 0;
    while (n)
    {
        parity = !parity;
        n      = n & (n - 1);
    }       
    return parity;
}
Above solution can be optimized by using lookup table. Please refer to Bit Twiddle Hacks[1st reference] for details.

Time Complexity: The time taken by above algorithm is proportional to the number of bits set. Worst case complexity is O(Logn).



    private static boolean isOddParity( final byte b )
        {
        int bb = b;
        int bitCount = 0;
        // Process bits right to left, shifting each bit in turn into the lsb position.
        for ( int i = 0; i < 8; i++, bb >>>= 1 )
            {
            if ( ( bb & 1 ) != 0 )
                {
                bitCount++;
                }
            }
        return ( bitCount & 1 ) != 0;
        }

     * Calculate parity of a single byte, using Eric Sosman's xor method
     * @return true of if odd parity, false if even parity
     */
    private static boolean isOddParityViaSosman( final byte b )
        {
        final int bb = b & 0xff;
        int parity = bb ^ ( bb >> 4 );
        parity ^= parity >> 2;
        parity ^= parity >> 1;
        return ( parity & 1 ) != 0;
        }

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