Detect if two integers have opposite signs | GeeksforGeeks

Given two signed integers, write a function that returns true if the signs of given integers are different, otherwise false.

bool oppositeSigns(int x, int y)

{

    return ((x ^ y) < 0);

}

bool oppositeSigns(int x, int y)

{

    return ((x ^ y) >> 31);

}

We can also solve this by using two comparison operators. 

bool oppositeSigns(int x, int y)

{

    return (x < 0)? (y >= 0): (y < 0);

}

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