DeeKaying - Geekiness @ IIT Roorkee: Printing all permutations of a string containing duplicate characters (C/C++)




Printing all distinct permutations of a string containing duplicate characters
 To avoid duplicates, we need to enforce the constraint that no character will be selected twice to place in the prefix before calling the subproblems. So, the resulting recursion gets modified as:


This simply means that at every stage of the recursion, pick only distinct characters. So, how do we do that? We pick the sk in ascending order.
char* full_string;
int counter = 0;
void permute(char *str, int length) {
    if(length == 0) {
        printf("%s\n", full_string);
        ++counter;
        return;
    } else {
        // Find the smallest char in the string set it to be the first character. Solve the subproblem for the smaller string.
        char *smallest = min_element(str, str + length);
        iter_swap(str, smallest);
        permute(str+1, length-1);
        
        // Look for the smallest element strictly greater than the first element of the current string
        char *smallest_greater = str + length;
        for(char *i = str+1; i != str+length; ++i)
            if(*i > *str && (smallest_greater == str + length || *i < *smallest_greater))
                smallest_greater = i;
        while(smallest_greater != str+length) {
            // If such an element is found, swap it into the first slot and recurse
            iter_swap(str, smallest_greater);
            permute(str+1, length-1);
            // Repeat the loop if possible for the next greater character
            smallest_greater = str + length;
            for(char *i = str+1; i != str+length; ++i)
                if(*i > *str && (smallest_greater == str + length || *i < *smallest_greater))
                    smallest_greater = i;

        }
    }
}


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