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We have been given an array, which contains random numbers, including zero. We have to move all zeros at the end of the array.
Key Point: Move element when scan, put zeros after dest pointer.
http://www.geeksforgeeks.org/move-zeroes-end-array/
void pushZerosToEnd(int arr[], int n)
{
    int count = 0;  // Count of non-zero elements
    // Traverse the array. If element encountered is non-zero, then
    // replace the element at index 'count' with this element
    for (int i = 0; i < n; i++)
        if (arr[i] != 0)
            arr[count++] = arr[i]; // here count is incremented Can be improved to avoid unnecessary assignement
    // Now all non-zero elements have been shifted to front and 'count' is
    // set as index of first 0. Make all elements 0 from count to end.
    while (count < n)
        arr[count++] = 0;
}

void move_zeroes(int a[], int size){
int i, dest = 0;
for(i =0; i<size; i++){
if(a[i] != 0){
a[dest++] = a[i];
}
}
for(i= dest; i<size; i++){
a[i] = 0;
}
printf("\n");
for(i= 0; i<size; i++){
printf("%d ", a[i]);
}
}
http://comproguide.blogspot.com/2013/10/moving-zeroes-to-end-of-array.html
The algorithm is simple, we take two  indices , one to loop through the entire array, and another to keep track of the non-zero elements. Once we loop through all the elements, we can fill the remaining spaces with zeros.
public static void moveZerosToEnd(int[] array)
{
int resInd = 0;// to keep track of non-zero elements in the final array
int i;
for( i = 0; i < array.length; i++ )
{
if( array[i] > 0 )
{
if( i != resInd ) //Avoid self copy
array[resInd] = array[i];
resInd++;
}
}
//Fill the remaining entries with 0
while( resInd < array.length )
{
array[resInd] = 0;
resInd++;
}
}
Read full article from Algorithms and Me: Arrays : Move all zeros at the end of the array

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