Permutation, Subset, All group of Palindrome


http://allenlipeng47.com/PersonalPage/index/view/194/nkey
    public static List<List<String>> getPermutation(String str) {
        List<List<String>> result = new ArrayList<List<String>>();
        getPermutationUtil(str, 0, result, new ArrayList<String>());
        return result;
    }

    public static void getPermutationUtil(String str, int start, List<List<String>> result, List<String> currResult) {
        if(start==str.length()) {
            ArrayList<String> curr = new ArrayList<String>(currResult);
            result.add(curr);
        }
        else {
            for(int i=start; i<str.length(); i++) {
                String currStr = str.substring(start, i+1);
                currResult.add(currStr);
                getPermutationUtil(str, i + 1, result, currResult);
                currResult.remove(currResult.size()-1);
            }
        }
    }
https://github.com/allenlipeng47/algorithm/blob/master/src/main/java/com/pli/project/algorithm/array/SuperSet.java
public class SuperSet {
    public static void main(String[] args) {
        char[] chs = {'a', 'b', 'c', 'd'};
//        printSuperSet(chs);
        List<List<Character>> result = getSuperSet(chs);
        System.out.println(result);
    }

    public static List<List<Character>> getSuperSet(char[] chs) {
        List<List<Character>> result = new ArrayList<List<Character>>();
        getSuperSetUtil(chs, 0, result, new ArrayList<Character>());
        return result;
    }

    public static void getSuperSetUtil(char[] chs, int start, List<List<Character>> result, List<Character> currResult) {
        if(start==chs.length) {
            ArrayList<Character> curr = new ArrayList<Character>(currResult);
            result.add(curr);
        }
        else {
            //count current char
            currResult.add(chs[start]);
            getSuperSetUtil(chs, start + 1, result, currResult);
            currResult.remove(currResult.size()-1);
            //doesn't count current char
            getSuperSetUtil(chs, start+1, result, currResult);
        }
    }

    public static void printSuperSet(char[] chs) {
        List<List<Character>> sets = new ArrayList<List<Character>>();
        int size = (int)Math.pow(2, chs.length);
        for(int i=0; i<size; i++) {
            List<Character> list = new ArrayList<Character>();
            for(int j=0; j<chs.length; j++) {
                if(((1<<j)&i)>0) {
                    list.add(chs[j]);
                }
            }
            sets.add(list);
        }
        System.out.println(sets);
    }
}
https://github.com/allenlipeng47/algorithm/blob/master/src/main/java/com/pli/project/algorithm/array/SuperSet.java
Given a string s, partition s such that every substring of the partition is a palindrome.
Return the minimum cuts needed for a palindrome partitioning of s.
For example, given s = "aab",
Return 1 since the palindrome partitioning ["aa","b"] could be produced using 1 cut.
public class AllPalindromePartition {
    public static void main(String[] args) {
        String str = "abacbdbc";
        System.out.println(getAllPalindromePartition(str));
    }

    public static List<List<String>> getAllPalindromePartition(String str) {
        List<List<String>> result = new ArrayList<List<String>>();
        getAllPalindromePartitionUtil(str, 0, result, new ArrayList<String>());
        return result;
    }

    public static void getAllPalindromePartitionUtil(String str, int start, List<List<String>> result, List<String> currResult) {
        if(start==str.length()) {
            ArrayList<String> curr = new ArrayList<String>(currResult);
            result.add(curr);
        }
        else {
            for(int i=start; i<str.length(); i++) {
                String currStr = str.substring(start, i+1);
                if(isPalindrome(currStr)) {
                    currResult.add(currStr);
                    getAllPalindromePartitionUtil(str, i + 1, result, currResult);
                    currResult.remove(currResult.size()-1);
                }
            }
        }
    }

    public static boolean isPalindrome(String str) {
        int left=0, right=str.length()-1;
        while(left<right) {
            if(str.charAt(left)==str.charAt(right)) {
                left++;
                right--;
            }
            else {
                return false;
            }
        }
        return true;
    }

}

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