Couple elimination - Remove Pairs

Problem solving with programming: Couple elimination problem
Given a string of some symbols, write a program to transform a string by repeatedly eliminating two same symbols occurring together.
For example if the input string is 'RGGB' it will be reduced to 'RB' because 'GG' can be eliminated.

Here are some more examples of input - output
Input   | Output
-------------------
GBRRBR  | GR
BGRGRR  | BGRG

 char string[MAX];
 char temp[MAX];
 
 cin>>string;
 int i;
 int tempInd = 0; //to track temp string
 
 for( i = 0 ; string[i] != '\0' ; i++)
 {
  //If temp string has atleast one character
  if( tempInd > 0)
  {
   //If previous, and current chars are same, erase
   if( temp[tempInd-1] == string[i] )
   {
    tempInd--;
   }
   else//not same, append the char to temp
   {
    temp[tempInd++] = string[i];
   }
  }
  else //temp is empty, simply append the character
  {
   temp[tempInd++] = string[i];
  } 
 }
 //append the NULL character at the end
 temp[tempInd] = '\0';
 //print the transformed string
 cout<<temp<<endl;

http://tech-queries.blogspot.com/2011/02/remove-pairs.html

1. void remove_pair(char* input)  
2. {  
3.     int len = strlen(input);  
4.     int i, j = 0;  
5.       
6.     for (i=1; i <= len; i++)  
7.     {  
8.         //Cancel pairs  
9.         while ((input[i] == input[j]) && (j >= 0))  
10.         {  
11.             i++;  
12.             j--;  
13.         }  
14.         input[++j] = input[i];  // if ++j ==i, don't copy
15.     }  
16.     return;  
17. } 

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