Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
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bool hasPathSum(TreeNode *root, int sum) {        // Start typing your C/C++ solution below        // DO NOT write int main() function        if (root==NULL) {return false;}        if ( (root->left==NULL) && (root->right==NULL) && (sum-root->val==0) ) {return true;}        return (hasPathSum(root->left, sum-root->val) || hasPathSum(root->right, sum-root->val));    }