Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.
The simplest solution is using PriorityQueue. The elements of the priority queue are ordered according to their natural ordering, or by a Comparator provided at queue construction time (in this case).
public ListNode mergeKLists(ArrayList<ListNode> lists) { if (lists.size() == 0) return null; //PriorityQueue is a sorted queue PriorityQueue<ListNode> q = new PriorityQueue<ListNode>(lists.size(), new Comparator<ListNode>() { public int compare(ListNode a, ListNode b) { if (a.val > b.val) return 1; else if(a.val == b.val) return 0; else return -1; } }); //add first node of each list to the queue for (ListNode list : lists) { if (list != null) q.add(list); } ListNode head = new ListNode(0); ListNode prev = head; while (q.size() > 0) { ListNode temp = q.poll(); prev.next = temp; //keep adding next element of each list if (temp.next != null) q.add(temp.next); prev = prev.next; } return head.next; }Read full article from LeetCode – Merge k Sorted Lists (Java)