https://leetcode.com/problems/maximum-difference-between-node-and-ancestor/
X. https://leetcode.com/problems/maximum-difference-between-node-and-ancestor/discuss/274610/JavaC%2B%2BPython-Top-Down
Given the
root
of a binary tree, find the maximum value V
for which there exists different nodes A
and B
where V = |A.val - B.val|
and A
is an ancestor of B
.
(A node A is an ancestor of B if either: any child of A is equal to B, or any child of A is an ancestor of B.)
Example 1:
Input: [8,3,10,1,6,null,14,null,null,4,7,13] Output: 7 Explanation: We have various ancestor-node differences, some of which are given below : |8 - 3| = 5 |3 - 7| = 4 |8 - 1| = 7 |10 - 13| = 3 Among all possible differences, the maximum value of 7 is obtained by |8 - 1| = 7.
Note:
- The number of nodes in the tree is between
2
and5000
. - Each node will have value between
0
and100000
X. https://leetcode.com/problems/maximum-difference-between-node-and-ancestor/discuss/274610/JavaC%2B%2BPython-Top-Down
We pass the minimum and maximum values to the children,
At the leaf node, we return
At the leaf node, we return
max - min
through the path from the root to the leaf.
Java:
public int maxAncestorDiff(TreeNode root) {
return dfs(root, root.val, root.val);
}
public int dfs(TreeNode root, int mn, int mx) {
if (root == null) return mx - mn;
mx = Math.max(mx, root.val);
mn = Math.min(mn, root.val);
return Math.max(dfs(root.left, mn, mx), dfs(root.right, mn, mx));
}