LeetCode 383 - Ransom Note


Related:
LeetCode 383 - Ransom Note
LeetCode 691 - Stickers to Spell Word

https://www.hrwhisper.me/leetcode-ransom-note/

Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
will 
return 
false. 


Each 
letter
 in
 the
 magazine 
string 
can
 only 
be
 used 
once
 in
 your 
ransom
 note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true

    public boolean canConstruct(String ransomNote, String magazine) {
        int[] cnt = new int[26];
        for (int i = 0; i < magazine.length(); i++) cnt[magazine.charAt(i) - 97]++;
for (int i = 0; i < ransomNote.length(); i++) if (--cnt[ransomNote.charAt(i) - 97] < 0) return false;
return true;
    }
http://thealphaking01.blogspot.com/2016/08/leetcode-solution-383-ransom-note.html


http://www.jianshu.com/p/5950dc7c75a5
Use hashmap - code is much complex
   public boolean canConstruct(String ransomNote, String magazine) {
    Map<Character,Integer> charmap = new HashMap<>();
    //循环把杂志中出现的单个字符计数,确定每个字符的出现频数~~
    for(int i = 0; i<magazine.length(); i++) {
        char c = magazine.charAt(i);
        if (charmap.containsKey(c)) {
            int count = (int)charmap.get(c);
            count++;
            charmap.put(c, count);
        }else {
            charmap.put(c, 1);
        }
    }
    //循环勒索信字符,每出现杂志中存在的字符,就把杂志中此字符频数减一。循环中,如果没得减了,就确定其无法构成信件!
    for(int i = 0; i<ransomNote.length() ;i++) {
        char c = ransomNote.charAt(i);
        if (charmap.containsKey(c)) {
            int count = (int)charmap.get(c);
            count--;
            if (count<0) {
                return false;
            }else {
                 charmap.put(c, count);
            }
        }else {
            return false;
        }
    }
    return true;
}

http://thealphaking01.blogspot.com/2016/08/leetcode-solution-383-ransom-note.html
    def canConstruct(self, ransomNote, magazine):
        """
        :type ransomNote: str
        :type magazine: str
        :rtype: bool
        """
        a = {}
        b = {}
        for i in magazine:
            a[i] = a.get(i,0)+1
        for i in ransomNote:
            b[i]=b.get(i,0)+1
        val=True
        for i in b.keys():
            if(a.get(i,0)<b[i]):
                val=False
                break
        return val

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