Google – Sort Squares


Google – Sort Squares
有一个sorted array of doubles, 要求返回另一个sorted array, 其中每个元素是input array里每个元素的平方。
[Solution]
Two pointers
[Note]
注意负数的情况,负数的平方是递减的。
还有一点要特别注意的是,Java中有个精度问题,注意到code里用了BigDecimal来做乘法,这是因为如果直接用double做乘法
0.2 * 0.2 = 0.04000000000000001.
BigDecimal可以解决。就因为这一点,给了4星,要记住。算法本身其实就是1星题目…

  public double[] sortedSquares(double[] nums) {
    double[] result = new double[nums.length];
    if (nums == null || nums.length == 0) {
      return result;
    }
     
    int k = nums.length - 1;
    int l = 0;
    int r = nums.length - 1;
    while (l <= r) {
      if (nums[l] * nums[l] > nums[r] * nums[r]) {
        result[k--] = new BigDecimal(String.valueOf(nums[l])).multiply(new BigDecimal(String.valueOf(nums[l]))).doubleValue();
        l++;
      }
      else {
        result[k--] = new BigDecimal(String.valueOf(nums[r])).multiply(new BigDecimal(String.valueOf(nums[r]))).doubleValue();
        r--;
      }
    }
    return result;
  }
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