Wednesday, September 7, 2016

Active and Inactive cells after k Days - GeeksforGeeks


Active and Inactive cells after k Days - GeeksforGeeks
Given a binary array of size n where n > 3. A true (or 1) value in the array means active and false (or 0) means inactive. Given a number k, the task is to find count of active and inactive cells after k days. After every day, status of i'th cell becomes inactive if its left and right cells have same value, i.e., either both are 0 or both are 1.
Since there are no cells before leftmost and after rightmost cells, the value cells before leftmost and after rightmost cells is always considered as 0 (or inactive).

The only important thing is to make sure that we maintain a copy of given array because we need previous values to update for next day. Below are detailed steps.
  1. First we copy the cells[] array into temp[] array and make changes in temp[] array according to given condition.
  2. In the condition, it is given that if immediate left and right cell of i’th cell either inactive or active the next day i becomes inactive i.e; (cells[i-1] == 0 and cells[i+1] == 0) or (cells[i-1] == 1 and cells[i+1] == 1) then cells[i] = 0, these conditions can be applied using XOR of cells[i-1] and cells[i+1].
  3. For 0’th index cell temp[0] = 0^cells[1] and for (n-1)’th index cell temp[n-1] = 0^cells[n-2].
  4. Now for index 1 to n-2, do the following operation temp[i] = cells[i-1] ^ cells[i+1]
  5. Repeat the process till k days are completed.
// cells[] - store current status of cells
// n - Number of cells
// temp[] - to perform intermediate operations
// k - number of days
// active - count of active cells after k days
// inactive - count of active cells after k days
void activeAndInactive(bool cells[], int n, int k)
{
    // copy cells[] array into temp [] array
    bool temp[n];
    for (int i=0; i<n ; i++)
        temp[i] = cells[i];
 
    // Iterate for k days
    while (k--)
    {
        // Finding next values for corner cells
        temp[0]   = 0^cells[1];
        temp[n-1] = 0^cells[n-2];
 
        // Compute values of intermediate cells
        // If both cells active or inactive, then temp[i]=0
        // else temp[i] = 1.
        for (int i=1; i<=n-2; i++)
            temp[i] = cells[i-1] ^ cells[i+1];
 
        // Copy temp[] to cells[] for next iteration
        for (int i=0; i<n; i++)
            cells[i] = temp[i];
    }
 
    // count active and inactive cells
    int active = 0, inactive = 0;
    for (int i=0; i<n; i++)
        (cells[i] == 1)? active++ : inactive++;
 
    printf("Active Cells = %d, Inactive Cells = %d",
           active, inactive);
}
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