Friday, December 11, 2015

蓝桥杯程序设计大赛真题及解析 >> 振兴中华


蓝桥杯程序设计大赛真题及解析 » 振兴中华
小明参加了学校的趣味运动会,其中的一个项目是:跳格子。

地上画着一些格子,每个格子里写一个字,如下所示:


从我做起振
我做起振兴
做起振兴中
起振兴中华

比赛时,先站在左上角的写着“从”字的格子里,可以横向或纵向跳到相邻的格子里,但不能跳到对角的格子或其它位置。一直要跳到“华”字结束。

要求跳过的路线刚好构成“从我做起振兴中华”这句话。

请你帮助小明算一算他一共有多少种可能的跳跃路线呢?

int main( )  
{  
    char c_i = 0;  
    char c_j = 0;  
    char c_arr[4][5] = {0};  
 
    clock_t start, finish;    
    start = clock();   
 
    for(c_i=0; c_i<4; c_i++)  
        c_arr[c_i][0] = 1;  
 
    for(c_j=0; c_j<5; c_j++)  
        c_arr[0][c_j] = 1;  
 
    for(c_i=1; c_i<4; c_i++)  
        for(c_j=1; c_j<5; c_j++)  
            c_arr[c_i][c_j] = c_arr[c_i-1][c_j] + c_arr[c_i][c_j-1] ;  
    printf("总共有%d种路线\n", c_arr[3][4]);  
 
 
    finish = clock();    
    printf( "\n\n\n程序运行时间:%.3f ms\n", (double)(finish - start));  
 
    return 0;  
}
http://www.mofriend.net/node/449
int s=0;
void walk(int x,int y)
{
 if(x>3 || y>4)
  return;
 if(x==3 && y==4)
 {
  s++;
  return;
 }
 walk(x+1,y);
 walk(x,y+1);
}
int main()
{
 walk(0,0);
 printf("%d",s);
 return 0;
}
http://www.zhuangjingyang.com/%E6%8C%AF%E5%85%B4%E4%B8%AD%E5%8D%8E.html
void find(int i,int j,int cur)
{
if(t[i][j]==8){
count++;
return;
}
if(i>0&&t[i-1][j] == cur+1)
find(i-1, j,cur+1);
if(i<3&&t[i+1][j] == cur+1) find(i+1, j, cur+1); if(j>0&&t[i][j-1] == cur+1)
find(i, j-1, cur+1);
if(j<4&&t[i][j+1] == cur+1)
find(i, j+1, cur+1);

return;
}

int main()
{
find(0, 0, 1);
printf("%d\n",count);
return 0;
}
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