[CareerCup][Google Interview] 实现一个具有get_min的Queue - chkkch - 博客园


[CareerCup][Google Interview] 实现一个具有get_min的Queue - chkkch - 博客园

Implement a queue in which push_rear(), pop_front() and get_min() are all constant time operations.

http://www.careercup.com/question?id=7263132给出了很精彩的解答。

主要的思想是维护一个min_queue,保存当前队列最小值,当新加入一个元素时,min_queue遵照这样的规则

从min_queue的尾部开始和新加入元素(key)比较,当min_queue.back() > key时,弹出back(),直到back()<= key,或者min_queue为空。

当要返回min时,return min_queue.front()

而pop()时,比较queue.front() == min_queue.front(),相等则min_queue.pop_front()

这里,最关键的思想是后来的key和min_queue从后往前比较,能够保证min_queue是一个非降序列,这样就能维护一个当前队列的最小值序列。

分摊下来,每个操作O(1)


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