## Monday, January 30, 2017

### Leetcode 492 - Construct the Rectangle

https://leetcode.com/problems/construct-the-rectangle/
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:
1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.
Example:
Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:
1. The given area won't exceed 10,000,000 and is a positive integer
2. The web page's width and length you designed must be positive integers.
https://discuss.leetcode.com/topic/76314/3-line-clean-and-easy-understand-solution
The W is always less than or equal to the square root of area
so we start searching at sqrt(area) till we find the result
public int[] constructRectangle(int area) {
int w = (int)Math.sqrt(area);
while (area%w!=0) w--;
return new int[]{area/w, w};
}
http://www.wonter.net/archives/1102.html

1.  vector<int> constructRectangle(int area)
2.  {
3.  int l, w;
4.  int t = sqrt(area);
5.  for(int i = t; i >= 1; --i)
6.  {
7.  if(area % i == 0)
8.  {
9.  w = i;
10.  break;
11.  }
12.  }
13.  l = area / w;
14.  return vector<int>{l, w};
15.  }