Sort Food | tech::interview


Sort Food | tech::interview
输入一个字符串,它包含的是『食物-重量』对。解析之,按食物重量降序排序输出List. (重量一致可放在一起)
特别情况:
  1. 当食物后面跟的也是食物,表明前面的食物是默认重量,比如5.
    在例子1中:crab后面直接跟了hotdog,那么crab的重量是5
  2. 在例子4中,2.0表示的是食物,这个食物的名字就叫2.0 因为它前面已经完成了
    一个食物-重量对(pizza, 500),但是当数字直接出现在食物后,它就一定是重量,
    比如例子2,3中的1,500都是重量。
注意:输入字符串前后可能有若干冗余空格,食物/重量之间也可能有冗余空格,请忽略所有冗余空格。
4个例子(默认重量 = 5):

1
2
3
4
sort_food("crab hotdog 9.0 chicken 9.2", 5);
sort_food(" pizza 1 hotdog 2.0", 5);
sort_food("pizza 500 hotdog 2.0 ", 5);
sort_food(" pizza 500 2.0 ", 5);

输出:
chicken hotdog crab
hotdog pizza
pizza hotdog
pizza 2.0
注意double在map里作为key比较,要手写一个compare类,不然会有精度问题。
void sort_food(const string& food_list, double def_weight) {
struct comp {
bool operator()( double a, double b ) const {
return (abs(a - b) > 1e-5) && (a > b);
}
};
map<double, vector<string>, comp> food;
string last_food;
for(int begin = -1, i = 0; i <= food_list.length(); ++i) {
char c = food_list[i];
if(begin == -1 && (c != ' ' && c != '\0')) {
begin = i;
} else if (begin != -1 && (c == ' ' || c == '\0')) {
auto word = food_list.substr(begin, i - begin);
if(last_food.empty()) {
last_food = word;
} else {
double weight = atof(word.c_str());
if(weight > 1e-5) { // valid weight
food[weight].push_back(last_food);
last_food.clear();
} else { // food
food[def_weight].push_back(last_food);
last_food = word;
}
}
begin = -1;
}
}
if(!last_food.empty()) food[def_weight].push_back(last_food);
for(auto& p : food)
for(auto &s : p.second) cout << s << " ";
cout << endl;
}

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