[SPOJ] ONP – Transform the Expression


http://www.chenguanghe.com/category/spoj/
http://www.spoj.com/problems/ONP/
Transform the algebraic expression with brackets into RPN form (Reverse Polish Notation). Two-argument operators: +, -, *, /, ^ (priority from the lowest to the highest), brackets ( ). Operands: only letters: a,b,...,z. Assume that there is only one RPN form (no expressions like a*b*c).

Input

t [the number of expressions <= 100]
expression [length <= 400]
[other expressions]
Text grouped in [ ] does not appear in the input file.

Output

The expressions in RPN form, one per line.

Example

Input:
3
(a+(b*c))
((a+b)*(z+x))
((a+t)*((b+(a+c))^(c+d)))

Output:
abc*+
ab+zx+*
at+bac++cd+^*
一个代数表达式转换成Reverse Polish Notation. 分析: wiki上就有规则. 其实这个题只有三个规则: 看到(, 忽略 看到操作符(加减乘除)入栈 看到), 出栈,打印 其余直接打印

    public void solve(int testNumber, InputReader in, OutputWriter out) {
        String s = in.readLine();
        out.printLine(infixToPostfix(s));
    }
    public String infixToPostfix(String infix) {
        Stack<Character> st = new Stack<>();
        StringBuffer sb = new StringBuffer();
        String opt = "+-*/^";
        for (int i = 0; i < infix.length(); i++) {
            Character c = infix.charAt(i);
            if (c.equals('('))
                continue;
            else if (opt.contains(c.toString()))
                st.push(c);
            else if (c.equals(')'))
                sb.append(st.pop());
            else
                sb.append(c);
        }
        return sb.toString();
    }



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