Monday, August 8, 2016

Google – Team Match


Google – Team Match
有n个player, n是2的倍数,排名1 to n. 每次比赛会让最好的对阵最差的,然后淘汰掉一半人,继续比赛直到只剩一个人位置。
要求返回一个字符串表示整个对阵过程。
比如n = 8, 那么应该return (((1, 8), (4, 5)), ((2, 7), (3, 4)))。
因为第一轮比赛之后胜者为8,7,6,5。 第二轮就应该是(8, 5)和(7, 6)。
[Solution]
这题第一反应应该是recursion。其实这里面有个tail-recursion的概念。
当然Iterative也可以做,但不是很熟练这样的解法,以后需要多练一下。
// Iterative
class Solution {
  public String teamMatch(int n) {
    String[] team = new String[n + 1];
    for (int i = 1; i <= n; i++) {
       team[i] = String.valueOf(i);
     }
     while (n > 1) {
      for (int i = 1; i <= n / 2; i++) {
        team[i] = print(team[i], team[n - i + 1]);
      }
      n /= 2;
    }
    return team[1];
  }
  private String print(String i, String j) {
    return String.format("(%s, %s)", i, j);
  }
}
// tail recursion
class Solution2 {
  public String teamMatch(int n) {
    String[] team = new String[n];
    for (int i = 0; i < n; i++) {
      team[i] = String.valueOf(i + 1);
    }
    return recur(team);
  }
  private String recur(String[] team) {
    if (team.length == 1) {
      return team[0];
    }
    int n = team.length;
    String[] newTeam = new String[n / 2];
    for (int i = 0; i < n / 2; i++) {
      newTeam[i] = String.format("(%s, %s)", team[i], team[n - i - 1]);
    }
    return recur(newTeam);
  }
}
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