Monday, August 8, 2016

Google – Shuffle With Blank


Google – Shuffle With Blank
输入一个unsorted array, 其中缺了一个值,比如[0, 2, _, 3], 要求移动数字使得每个数都在对应的index上,但是移动的要求是数字只能移动到空的位置上。
[Solution]
首先这题的题意可能和原题有出入,面经讲的不是很清楚。但是即使就按上面题目的描述来做,code也没有想象中的好写。
其实就是换种方法swap。把每个数字换到对应的index上,除非对应的index正好empty,否则empty位置不变,继续换当前位置的数字(就是本来在index上刚刚换过来的)。

class
Solution {
  public void shuffle(int[] nums) {
    if (nums == null || nums.length == 0) {
      return;
    }
 
    int emptyIdx = -1;
    for (int i = 0; i < nums.length; i++) {
      if (nums[i] == -1) {
        emptyIdx = i;
        break;
      }
    }
 
    shuffle(nums, emptyIdx);
  }
 
  private void shuffle(int[] nums, int emptyIdx) {
    int i = 0;
    while (i < nums.length) {
      if (i != emptyIdx && nums[i] != i && nums[i] < nums.length) {
        int newEmptyIdx = swap(nums, i, nums[i], emptyIdx);
        if (emptyIdx != newEmptyIdx) {
          i++;
        }
        emptyIdx = newEmptyIdx;
      }
      else {
        i++;
      }
    }
  }
 
  private int swap(int[] nums, int i, int j, int emptyIdx) {
    if (j == emptyIdx) {
      nums[j] = nums[i];
      nums[i] = -1;
      return i;
    }
    else {
      nums[emptyIdx] = nums[j];
      nums[j] = nums[i];
      nums[i] = nums[emptyIdx];
      nums[emptyIdx] = -1;
      return emptyIdx;
    }
  }
}
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