In-place convert matrix in specific order - GeeksforGeeks


In-place convert matrix in specific order - GeeksforGeeks
Write a code to convert a matrix in specific way without using extra space.

Input:
      1 2 3
      4 5 6
      7 8 9

Output:
      1 6 7
      2 5 8
      3 4 9
every even column in output matrix has elements of corresponding row in input matrix in opposite order.

void transformMatrix(int *A, int r, int c)
{
    // Invert even rows
    for (int i = 1; i < r; i = i + 2)
        for (int j1 = 0, j2 = c - 1; j1 < j2; j1++, j2--)
            swap(*(A + i*c + j1), *(A + i*c + j2));
 
    // Rest of the code is from below post
    int size = r*c - 1;
    int t; // holds element to be replaced, eventually
           // becomes next element to move
    int next; // location of 't' to be moved
    int cycleBegin; // holds start of cycle
 
    bitset<HASH_SIZE> b; // hash to mark moved elements
 
    b.reset();
    b[0] = b[size] = 1;
    int i = 1; // Note that A[0] and A[size-1] won't move
    while (i < size)
    {
        cycleBegin = i;
        t = A[i];
        do
        {
            // Input matrix [r x c]
            // Output matrix 1
            // i_new = (i*r)%(N-1)
            next = (i*r)%size;
            swap(A[next], t);
            b[i] = 1;
            i = next;
 
        while (i != cycleBegin);
 
        // Get Next Move (what about querying
        // random location?)
        for (i = 1; i < size && b[i]; i++)
            ;
    }
}
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