UVA – 673 – PARENTHESES BALANCE


https://belbesy.wordpress.com/2011/04/16/uva-00673-parentheses-balance/
You are given a string consisting of parentheses () and []. A string of this type is said to be correct:
(a)
if it is the empty string
(b)
if A and B are correct, AB is correct,
(c)
if A is correct, (A) and [A] is correct.
Write a program that takes a sequence of strings of this type and check their correctness. Your program can assume that the maximum string length is 128.

Input 

The file contains a positive integer n and a sequence of n strings of parentheses () and [], one string a line.

Output 

A sequence of Yes or No on the output file.

Sample Input 


3
([])
(([()])))
([()[]()])()

Sample Output 

Yes
No
Yes
    public static void main(String[] args) throws IOException {
        BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
 
        int N = Integer.parseInt(bf.readLine());
        while (N-- != 0) {
            boolean bad = false;
            char[] cs = bf.readLine().toCharArray();
            Stack<Character> stk = new Stack<Character>();
            for (char c : cs) {
                if (c == '[' || c == '(') {
                    stk.push(c);
                } else {
                    if (c == ']') {
                        if (stk.isEmpty() || stk.peek() == '(')     bad |= true;
                    } else if (c == ')') {
                        if (stk.isEmpty() || stk.peek() == '[')     bad |= true;
                    }
                    if (!stk.isEmpty())     stk.pop();
                }
            }
            if (!stk.isEmpty())     bad = true;
            System.out.println(bad ? "No" : "Yes");
        }
    }
http://samus250.blogspot.com/2013/09/uva-problem-parenthesis-balance.html
  public static boolean solve(String line) {
    Stack<Character> stack = new Stack<Character>();
    for (int i = 0; i < line.length(); i++) {
      char c = line.charAt(i);
       
      if (isOpening(c)) {
        // Push opening char to stack.
        stack.push(c);
      } else {
        // Verify closing parenthesis.
        if (stack.isEmpty()) {
          return false;
        } else {
          char cInStack = stack.pop();
          if (map(cInStack) != c) {
            return false;
          }
        }
      }
    }
     
    return stack.isEmpty();
  }
   
  /**
   * Returns whether a given char is an opening char.
   * @param c The char to classify.
   * @return True if it is an opening char, false otherwise.
   */
  public static boolean isOpening(char c) {
    switch (c) {
    case '(':
    case '[':
      return true;
    default:
      return false;
    }
  }
   
  /**
   * Maps opening chars to closing chars.
   * @param c The opening char.
   * @return The corresponding closing char.
   */
  public static char map(char c) {
    switch (c) {
    case '(':
      return ')';
    case '[':
      return ']';
    default:
      return ' ';
    }
  }



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